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pjudge
用户信息
taniya
Rating
1800
Contribution
7
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格言
$$\prod_{n=1}^\infty (1-x^n)=\sum_{k=-\infty}^\infty(-1)^kx^{\frac{k(3k-1)}{2}}=\sum_{k=0}^\infty(-1)^kx^{\frac{k(3k\pm 1)}{2}}$$
1800
7
/
$$\prod_{n=1}^\infty (1-x^n)=\sum_{k=-\infty}^\infty(-1)^kx^{\frac{k(3k-1)}{2}}=\sum_{k=0}^\infty(-1)^kx^{\frac{k(3k\pm 1)}{2}}$$